How do I display output of a python within Html in django?

Question

I'm trying parse my blog posts with rss using feedparser and displaying it within the html tags. How i can display it within html ? Any help would be really appreciated.

I have tried it using it within the views.py and

def gspace(request):
 d=feedparser.parse('http://glammingspace.blogspot.com/feeds/posts/defaultalt=rss')
    r = d.entries[0].summary
    response_html = '<br>'.join(r)
    return HttpResponse(response_html)

I have tried to display it in html , something like this

but it doesn't work fine .. help me to do it in better way.

Shahul Hameed · Accepted Answer · 2019-06-14 04:47:08Z

4

I assume you want to pass your blog posts to your template. For that, in Django, you can pass context variables to the template. So instead of simply returning an HttpResponse, try the following:

return render(request, "template.html", context)

Here, template.html is the HTML template file. The context would be a python dictionary which would contain posts. And you can use {{ context }} in the template to access the same. Ideally, if you add each blog post as an item to the dictionary, you can iterate over the context dictionary using {% for %} loop.

Also, don't forget to import render.

from django.shortcuts import render

edited Jun 14, 2019 at 4:47

answered Jun 14, 2019 at 4:31

Shahul Hameed

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1 Comment

Adärshrëddÿ Adëllï Over a year ago

Thank's shahul .!

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