I want to put python script output to HTML using Django with a button. When the user clicks the button again and it changes the random number again.
import random
num = ['1', '2', '3', '4', '5', '6', '7', '8', '9', '10']
print(random.choice(num))
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2 Answers
In your views.py file inside your app (all inside your Django project)... From the function that will display this random number, put:
from random import choice
def <function_you_are_using> (request):
nums = [1,2,3,4,5]
context = {"number": choice(nums)}
return render(request, '<function_you_are_using>', context)
Then, in your HTML, put:
<h1>{{ number }}</h1>
That should display the random-choice number. Hope it helps.
Comments
You could render this out in a template. This would take the function you have above and place it into a function based view. the function will take your list of numbers and assign the random number to the variable random_number, which is then passed in as context (on the return line).
# views.py
def random_num(request):
num = ['1', '2', '3', '4', '5', '6', '7', '8', '9', '10']
random_number = random.choice(num)
return render(request, 'random-number.html', {'random_number': random_number})
To pass this into the HTML template (see HTML below). This is taking the 'random_number' variable that you assigned in your view and rendering it in place of {{ random_number }} when the page loads.
<!-- random-number.html -->
<html>
<h1>Random Number: {{ random_number }}</h1>
<form action="{% url 'random-number' %}">
<input type="submit" value="Get New Number"/>
</form>
</html>
Sort of a lazy workaround since the "button" is just refreshing the page to call the function again and generate a new random number.
