Given an array and variable as following..
array = ['complete','in_progress','planned'];
value = 'planned';
I want to sort the array always starting with the 'value' variable the output should display.
array = ['planned','in_progress','complete'];
eg.
array = ['complete','in_progress','planned'];
value = 'in_progress';
output would be...
array = ['in_progress','complete','planned'];
I tried different ways but I failed to come with a decent solution. Any clean and short ideas?
You can sort and give higher priority to value - if it matches one of the arguments, then it will be sorted before anything. If neither of the two items is value, then just sort normally.
const array = ['complete','in_progress','planned'];
const value = 'in_progress';
array.sort((a, b) => {
//a comes first
if (a == value) return -1;
//b comes first
if (b == value) return 1;
//neither matches `value` - compare them normally
return a.localeCompare(b);
});
console.log(array);And this is the shorter version of the same by (somewhat) abusing type coercion:
const array = ['complete','in_progress','planned'];
const value = 'in_progress';
array.sort((a,b) => ((a == value) * -1) || b == value || a.localeCompare(b));
console.log(array);From the top of my head you can try
array = ['complete','in_progress','planned'];
target = 'in_progress';
const answer = array.filter((element) => element !== target)
.sort()
.reduce((accumulator, value) => [...accumulator, value], [target]);
edit: I forgot it needs to be sorted.
unshift to add to the front. If you really want to do it in one continuous operation, then why not just [target].concat(/* filter + sort */)? That's not that great, either but at least it's not using reduce for an operation that is so trivial.
"complete"moved to the end? It is neither keeping the original relative position nor is it sorted alphabetically