Python : loop making variable

Question

I'm trying to do a simple python program able to print the right variable depend of the incremented value.

a1 = 'hiya'
a2 = 'i love cats'

lignenum = 2
incremented_value = 1
while incremented_value <= lignenum:
    print(a, incremented_value) 
     incremented_value += 1

i want my program to render :

'hiya' 'i love cats'

Thanks for reading me

Where is a and p defined?

Mark
– Mark

2019-11-27 17:01:56 +00:00
Commented Nov 27, 2019 at 17:01 — Mark
– Mark, Commented Nov 27, 2019 at 17:01
sorry p is incremented value

Séverine F
– Séverine F

2019-11-27 17:02:22 +00:00
Commented Nov 27, 2019 at 17:02 — Séverine F
– Séverine F, Commented Nov 27, 2019 at 17:02
My true program have many more variable to print ^^^

Séverine F
– Séverine F

2019-11-27 17:14:03 +00:00
Commented Nov 27, 2019 at 17:14 — Séverine F
– Séverine F, Commented Nov 27, 2019 at 17:14

Celius Stingher · Accepted Answer · 2019-11-27 17:05:29Z

1

I would define a list with this values you would like to print, and then access them according to their index-value. That is:

arguments = ['hiya','i love cats']
lignenum = 1
incremented_value = 0
while incremented_value <= lignenum:
    print(arguments[incremented_value]) 
    incremented_value += 1

This prints:

hiya
i love cats

answered Nov 27, 2019 at 17:05

Celius Stingher

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tomgalpin · Accepted Answer · 2019-11-27 17:05:58Z

1

Use a list and iterate btween 0 and the length of the list. There are better ways to do this but a simple solution is below

a = []
a.append('hiya')
a.append('i love cats')

lignenum = len(a)
incremented_value = 0
while incremented_value <= lignenum:
    print(a[incremented_value]) 
     incremented_value += 1

answered Nov 27, 2019 at 17:05

tomgalpin

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