Filtering an array of objects from an array

Question

I have an array of objects lookups and an array filters. Now I want to filter the array from an array of objects using the object attribute name.

I used filter and some but I could not get the expected result.

EXPECTED RESULT:

[{id: 3, name: "Linkedin"}]

let lookups = [
{id: 1, name: "Twitter"},
{id: 2, name: "Facebook"},
{id: 3, name: "Linkedin"}
]

let filters = ["Facebook", "Twitter"]

const filtered = lookups.filter(lookup => filters.some(filter => filter.toLowerCase() != lookup.name.toLowerCase()));

console.log(filtered)

Maheer Ali · Accepted Answer · 2020-03-23 18:32:59Z

3

Your code gives those elements in result for which some of the values in filters is not equal to element's name. So for each element some of the name is not equal.

In other words you are using != with || which will always return true.

let a = "anything";
console.log(a !== "thing1" || a !== "thing2")

You need to use every() instead of some().

let lookups = [
{id: 1, name: "Twitter"},
{id: 2, name: "Facebook"},
{id: 3, name: "Linkedin"}
]

let filters = ["Facebook", "Twitter"]

const filtered = lookups.filter(lookup => filters.every(filter => filter.toLowerCase() !== lookup.name.toLowerCase()));

console.log(filtered)

edited Mar 23, 2020 at 18:32

answered Mar 23, 2020 at 18:27

Maheer Ali

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