Filter array of objects using arrays of values?

Question

Given the following array of objects:

var data = [
  {fruit: "apples", stock: false, season: true},
  {fruit: "peaches", stock: true, season: false},
  {fruit: "oranges", stock: false, season: false},
  {fruit: "pears", stock: false, season: true},
]

and these two arrays:

var fruits = ["apples", "peaches"]
var inv = ["stock"]

How can I filter the objects, from data, so that objects are kept:

if they have a fruit in the fruits array; AND
they have a property from the inv array which is set to true

So, in the above example, only peaches survive:

  var result = [
    {fruit: "peaches", stock: true, season: false}
  ]

The simplest approach would be three loops, hence... What have you tried so far? — Andreas
– Andreas, Commented Sep 19, 2018 at 17:08
what means "they have a property from the inv array which is set to true"? does a single property has to be set to true, or if more all? — Nina Scholz
– Nina Scholz, Commented Sep 19, 2018 at 17:12

Mark · Accepted Answer · 2018-09-19 17:07:53Z

3

I think you can just use filter with some() and includes():

var data = [
  {fruit: "apples", stock: false, season: true},
  {fruit: "peaches", stock: true, season: false},
  {fruit: "oranges", stock: false, season: false},
  {fruit: "pears", stock: false, season: true},
]

var fruits = ["apples", "peaches"]
var inv = ["stock"]

let filtered = data.filter(item => 
    fruits.includes(item.fruit) && inv.some(i => item[i]))

console.log(filtered)

answered Sep 19, 2018 at 17:07

Mark

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Comments

Nina Scholz · Accepted Answer · 2018-09-19 17:07:53Z

2

You could filter by looking in the fruits array with Array#includes and check the property by iterating inv with Array#every.

var data = [ { fruit: "apples", stock: false, season: true }, { fruit: "peaches", stock: true, season: false }, { fruit: "oranges", stock: false, season: false }, { fruit: "pears", stock: false, season: true }],
    fruits = ["apples", "peaches"],
    inv = ["stock"],
    result = data.filter(o => fruits.includes(o.fruit) && inv.every(k => o[k]));
   
console.log(result);

answered Sep 19, 2018 at 17:07

Nina Scholz

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3 Comments

Ram Over a year ago

It seems your should use some instead of the every: "they have a property from the inv array which is set to true".

Nina Scholz Over a year ago

this part is questionable.

Ram Over a year ago

Not a big deal anyways. OP can swap the methods according to his/her needs.

Just code · Accepted Answer · 2018-09-19 17:11:02Z

0

You can use combination of filter and every here.

var data = [
  {fruit: "apples", stock: false, season: true},
  {fruit: "peaches", stock: true, season: false},
  {fruit: "oranges", stock: false, season: false},
  {fruit: "pears", stock: false, season: true},
]

var fruits = ["apples", "peaches"]
var inv = ["stock"]

var result= data.filter(a=> fruits.some(b=> b == a.fruit) && inv.every(k => a[k]));
console.log(result)

answered Sep 19, 2018 at 17:11

Just code

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Comments

sushant shrestha · Accepted Answer · 2018-09-19 17:35:52Z

0

var output = data.filter(val => {
    if (fruits.includes(val.fruit)) {
        return inv.filter(prop => {
            if (val[prop] == true)
                return val
        }).length > 0
    }
})
console.log(output)

I think this will do, if you just want to filter through.

answered Sep 19, 2018 at 17:35

sushant shrestha

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