PHP variable as input for img src attribute

Question

I am trying to make gallery which displays all the .jpg files in some local directory, but it makes me problem.

   <?php

   $directory = "img/";   
   $images = glob($directory."*.jpg");
   foreach($images as $image)
   {
       echo '<img src="file://'.$image.'" /><br />'
   }
   ?>

Somehow path to jpg file is not correctly passed to the src attribute, where I am wrong?

Assuming you get a broken image icon, what does right clicking say is the path that it's trying? What does "View source" on the browser show? Do modern browsers even allow file:// anymore? And you might want to have file://img/ as the path or whatever the full, absolute path is. — Mike
– Mike, Commented Nov 25, 2020 at 23:13

mrJ0ul3 · Accepted Answer · 2020-11-25 23:18:40Z

1

Just remove the file:// on the src.

from

echo '<img src="file://'.$image.'" /><br />';

to

echo '<img src="'.$image.'"/><br />';

answered Nov 25, 2020 at 23:18

mrJ0ul3

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