Javascript check if array all item exist in JSON array

Question

Compare all array item into JSON array object

const filterArray = ['Ford', 'Fiat'];

const showrooms = [{
    "Name": "Mark Auto",
    "Location": "Delhi",
    "Cars": ['Ford', 'BMW', 'Fiat']
  },
  {
    "Name": "Cardekho",
    "Location": "Mumbai",
    "Cars": ['Ford', 'Fiat']
  },
  {
    "Name": "Tata Arena",
    "Location": "Pune",
    "Cars": ['Ford', 'BMW']
  },
  {
    "Name": "Nexa Showroom",
    "Location": "Noida",
    "Cars": ['Suzuki', 'Ford', 'Tata', 'Fiat']
  }
]

I write code to filter data but not working.

const result = this.showrooms.filter(c=> this.filterArray.includes(c.Cars)).map(a=>a.Name);

Desired Output

['Mark Auto', 'Cardekho', 'Nexa Showroom']

Tibebes. M · Accepted Answer · 2021-01-07 07:34:02Z

2

You could use every to check if every showroom's cars include all of the cars in the filterArray

const filterArray = ['Ford', 'Fiat'];

const showrooms = [
  {
    Name: "Mark Auto",
    Location: "Delhi",
    Cars: ["Ford", "BMW", "Fiat"],
  },
  {
    Name: "Cardekho",
    Location: "Mumbai",
    Cars: ["Ford", "Fiat"],
  },
  {
    Name: "Tata Arena",
    Location: "Pune",
    Cars: ["Ford", "BMW"],
  },
  {
    Name: "Nexa Showroom",
    Location: "Noida",
    Cars: ["Suzuki", "Ford", "Tata", "Fiat"],
  },
];

const res = showrooms
  .filter((s) => filterArray.every((c) => s.Cars.includes(c)))
  .map((s) => s.Name);

console.log(res);

edited Jan 7, 2021 at 7:34

Tibebes. M

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answered Jan 7, 2021 at 7:33

hgb123

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Comments

Nikhil Patil · Accepted Answer · 2021-01-07 07:33:20Z

1

Use every -

const filterArray = ['Ford', 'Fiat'];

const showrooms = [{
    "Name": "Mark Auto",
    "Location": "Delhi",
    "Cars": ['Ford', 'BMW', 'Fiat']
  },
  {
    "Name": "Cardekho",
    "Location": "Mumbai",
    "Cars": ['Ford', 'Fiat']
  },
  {
    "Name": "Tata Arena",
    "Location": "Pune",
    "Cars": ['Ford', 'BMW']
  },
  {
    "Name": "Nexa Showroom",
    "Location": "Noida",
    "Cars": ['Suzuki', 'Ford', 'Tata', 'Fiat']
  }
];
const result = showrooms.filter(c => filterArray.every(e => c.Cars.includes(e))).map(a => a.Name);
console.log(result);

answered Jan 7, 2021 at 7:33

Nikhil Patil

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Comments

Nghi Nguyen · Accepted Answer · 2021-01-07 07:34:20Z

Just need update the condition inside you filter. The current doesn't return as your expected result.

const filterArray = ["Ford", "Fiat"];

const showrooms = [
  {
    Name: "Mark Auto",
    Location: "Delhi",
    Cars: ["Ford", "BMW", "Fiat"],
  },
  {
    Name: "Cardekho",
    Location: "Mumbai",
    Cars: ["Ford", "Fiat"],
  },
  {
    Name: "Tata Arena",
    Location: "Pune",
    Cars: ["Ford", "BMW"],
  },
  {
    Name: "Nexa Showroom",
    Location: "Noida",
    Cars: ["Suzuki", "Ford", "Tata", "Fiat"],
  },
];

const result = showrooms
  .filter((c) => {
     let existedInArray = true
     
     for(let i=0; i < filterArray.length; i++){
      if(!c.Cars.includes(filterArray[i])) existedInArray = false
     }
     return existedInArray
  })
  .map((a) => a.Name);
  
 console.log(result)

Sohanuzzaman Soad · Accepted Answer · 2021-01-07 07:39:49Z

const filterArray = ["Ford", "Fiat"];

const showrooms = [
  {
    Name: "Mark Auto",
    Location: "Delhi",
    Cars: ["Ford", "BMW", "Fiat"],
  },
  {
    Name: "Cardekho",
    Location: "Mumbai",
    Cars: ["Ford", "Fiat"],
  },
  {
    Name: "Tata Arena",
    Location: "Pune",
    Cars: ["Ford", "BMW"],
  },
  {
    Name: "Nexa Showroom",
    Location: "Noida",
    Cars: ["Suzuki", "Ford", "Tata", "Fiat"],
  },
];

const result = showrooms
  .filter((c) => {
     let existedInArray = true
     
     for(let i=0; i < filterArray.length; i++){
      if(!c.Cars.includes(filterArray[i])) existedInArray = false
     }
     return existedInArray
  })
  .map((a) => a.Name);
  
 console.log(result)

I think This Will Works

Tai Ly · Accepted Answer · 2021-01-07 07:41:07Z

You could use reduce + every to solve this in one loop. When you do something combining filter and map, reduce is really a good way.

const filterArray = ['Ford', 'Fiat'];
const showrooms = [{
    "Name": "Mark Auto",
    "Location": "Delhi",
    "Cars": ['Ford', 'BMW', 'Fiat']
  },
  {
    "Name": "Cardekho",
    "Location": "Mumbai",
    "Cars": ['Ford', 'Fiat']
  },
  {
    "Name": "Tata Arena",
    "Location": "Pune",
    "Cars": ['Ford', 'BMW']
  },
  {
    "Name": "Nexa Showroom",
    "Location": "Noida",
    "Cars": ['Suzuki', 'Ford', 'Tata', 'Fiat']
  }
]


const result = showrooms.reduce((prev, curr) => {
  const isFilterCarsIncluded = filterArray.every(car => curr.Cars.includes(car));

  if (isFilterCarsIncluded) {
    return [...prev, curr.Name];
  }

  return prev;
}, []);

console.info(result);

Neal Ding · Accepted Answer · 2021-01-07 07:59:02Z

0

Demo:

showrooms
  .filter(showroom => filterArray.every(item => showroom.Cars.includes(item)))
  .map(showroom => showroom.Name);

Done.

answered Jan 7, 2021 at 7:59

Neal Ding

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Comments

Siva Kondapi Venkata · Accepted Answer · 2021-01-07 12:15:09Z

0

with reduce in one iteration, we can accumulate desired output

const combine = (arr, filters) =>
  arr.reduce((acc, { Name, Cars }) => {
    filters.every((car) => Cars.includes(car)) && acc.push(Name);
    return acc;
  }, []);

const filterArray = ["Ford", "Fiat"];

const showrooms = [
  {
    Name: "Mark Auto",
    Location: "Delhi",
    Cars: ["Ford", "BMW", "Fiat"],
  },
  {
    Name: "Cardekho",
    Location: "Mumbai",
    Cars: ["Ford", "Fiat"],
  },
  {
    Name: "Tata Arena",
    Location: "Pune",
    Cars: ["Ford", "BMW"],
  },
  {
    Name: "Nexa Showroom",
    Location: "Noida",
    Cars: ["Suzuki", "Ford", "Tata", "Fiat"],
  },
];

console.log(combine(showrooms, filterArray));

answered Jan 7, 2021 at 12:15

Siva Kondapi Venkata

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