How to print every error using try except in python

Question

I'm now learning how to handle multiple errors in python. While using try-except I want to print every error in try. There are two errors in try but the indexing error occurred first, so the program can't print a message about ZeroDivisionError. How can I print both IndexErrormessage and ZeroDivisionErrormessage?

Below is the code I wrote.

try:
    a = [1,2]
    print(a[3])
    4/0
except ZeroDivisionError as e:
    print(e)
except IndexError as e:
    print(e)

azro · Accepted Answer · 2021-01-24 10:27:14Z

2

As the IndexError occurs, it goes to the except, so the 4/0 is not executed, the ZeroDivisionError doesn't occur, to get both executed, use 2 different try-except

try:
    a = [1, 2]
    print(a[3])
except IndexError as e:
    print(e)

try:
    4 / 0
except ZeroDivisionError as e:
    print(e)

Giving

list index out of range
division by zero

answered Jan 24, 2021 at 10:27

azro

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Luke Skywalker · Accepted Answer · 2021-01-24 10:42:40Z

2

You cannot do that, when the first error occurs, your code executes except block unless you define multiple try-except blocks.

edited Jan 24, 2021 at 10:42

answered Jan 24, 2021 at 10:28

Luke Skywalker

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