Python, try except, print error line #

Question

I would like when there is an error that it would display what line the error occurred at. I am unsure how I can obtain the line # that the error happened at though. Any help would be appreciated.

def main():
    while True:
       try:
           function1()
           function2()
           function3()
       except:
           print('error occur at line ' + str(errorline))

Inspecting an interpreter stack is a way to go. [docs.python.org/2/library/inspect.html#the-interpreter-stack] — Łukasz Rogalski
– Łukasz Rogalski, Commented Feb 25, 2015 at 19:45

vaultah · Accepted Answer · 2015-02-25 20:02:49Z

3

Using traceback.extract_tb:

import sys
import traceback
try:
    # Your code
except:
    tb = sys.exc_info()[-1]
    print(traceback.extract_tb(tb, limit=1)[-1][1])

I added limit=1 for efficiency, to avoid loading the (possibly) huge traceback. You can't avoid indexing the list ([-1] to get the last element) though.

edited Feb 25, 2015 at 20:02

answered Feb 25, 2015 at 19:45

vaultah

46.9k12 gold badges120 silver badges145 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

aruisdante Over a year ago

extract_tb takes a limit param that can be used instead of indexing the array. Also, according to the doc, if you store the traceback reference returned by exc_info() you should always delete it or it creates a circular reference that is difficult to garbage collect.

vaultah Over a year ago

@aruisdante only important in Python 2.

Collectives™ on Stack Overflow

Python, try except, print error line #

1 Answer 1

2 Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

2 Comments

Your Answer

Sign up or log in

Post as a guest

Related