Can a Python nested function variable be used in other nested functions?

Question

I am currently working on a simple calculator program and I have run into a problem with taking data from a nested function and using it in another nested function.

Here is the portion of my code that this problem relates to:

def func():
  
  def func1():
    a = float(input("Enter first number: "))
    b = float(input("Enter second number: "))
  
  def func2():
    print(f"{a}, {b}")

  func1()
  func2()

func()

As you can see, func() is called which calls func1() and func2(). However, running this program results in NameError: name 'a' is not defined with an error reference line pointing towards the body of func2().

I know it is not possible to access a, b within func2() as they are only defined within func1(), but I cannot use the nonlocal statement as according to the documentation:

'names listed in a nonlocal statement ... must refer to pre-existing bindings in an enclosing scope.'

and func1() does not enclose func2().

More so, I am trying to avoid using the global statement or defining a and b in func() because it seems to be poor practise in any programming language (reference) and could lead to unintended side-effects later on in my program's development.

Is there any way to declare a and b as usable and modifiable anywhere within func(), whilst still defining it in func1?

You could return a and b values from func1 and pass them as parameters on func2 — Felipe Joaquín Pastén Cáceres
– Felipe Joaquín Pastén Cáceres, Commented Feb 21, 2021 at 13:19

Felipe Joaquín Pastén Cáceres · Accepted Answer · 2021-02-21 13:32:02Z

2

You just need to return them in func1 and pass the results to func2

def func1():
    a = float(input("Enter first number: "))
    b = float(input("Enter second number: "))
    return a, b

Then,

def func2(a, b):
    print(f"{a}, {b}")

And then when you call the functions you assign variables a and b to the result of func1 and pass them as parameters to func2,

a,b = func1()
func2(a, b)

You could initialize the variables in the scope of func but it is better to handle them as the return of the function, it easier to keep track of the algorithm that way.

answered Feb 21, 2021 at 13:32

Felipe Joaquín Pastén Cáceres

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Comments

Rivers · Accepted Answer · 2021-02-21 18:35:21Z

1

That's problem of scope.

You have 2 possibilities to make it work:

1. Return a and b in func1, and call func1 in func2:

def func():
  
    def func1():
      a = float(input("Enter first number: "))
      b = float(input("Enter second number: "))

      return (a,b)
  
    def func2():
      a,b = func1()
      print(f"{a}, {b}")

  
    func2()

func()

2. Define func2 in func1, and call func2 in func1 after its declaration, and call func1 in func, after its declaration:

def func():
  
    def func1():
      a = float(input("Enter first number: "))
      b = float(input("Enter second number: "))


  
      def func2():
        print(f"{a}, {b}")

  
      func2()
    func1()

func()

edited Feb 21, 2021 at 18:35

answered Feb 21, 2021 at 13:36

Rivers

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