As I am studying decorators, I noticed something strange :
def f():
... msg='aa'
... def a():
... print msg
... msg='bb'
... def b():
... print msg
... return a,b
...
>>> a,b = f()
>>> a()
bb
>>> b()
bb
>>>
Why a() returns 'bb' and not 'aa' ??
Because a and b have the same outer scope, in which msg is bound to 'bb'. Put them in separate functions if you want them to have separate scopes.
msg is not defined as a constant "aa". The variable survives in the local scope of f, and the inner functions a/b have access to that scope at any later time. As you overwrite the value of msg immediately, i.e. before calling a or b, they will read the new value.Both a and b have read access to the outer scope (the local scope of f). As you overwrite the value of msg, the later call to a/b will read the new value.
