Avoid multiple try except block in python

Question

I want to handle few function calls using try excpept block. Is there any better and cleaner way to do it. My current flow is

def handle_exception():
    try:
        x()
    except Exception:
        print("Failed to init module x")
    try:
        y()
    except Exception:
        print("Failed to init module y")
    try:
        z()
    except Exception:
        print("Failed to init module z")

Guy · Accepted Answer · 2021-07-07 06:25:56Z

3

You can invoke the modules in a loop

def handle_exception():
    modules = x, y, z
    for module in modules:
        try:
            module()
        except Exception:
            print(f'Failed to init module {module.__name__}')

If you want to pass parameters as well you can use dict to store the data

def handle_exception():
    modules = {x: [1, 2], y: 'asd', z: 5}
    for module, params in modules.items():
        try:
            module(params)
        except Exception:
            print(f'Failed to init module {module.__name__}')

edited Jul 7, 2021 at 6:25

answered Jul 7, 2021 at 6:17

Guy

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2 Comments

Pranjal Doshi Over a year ago

Thanks... This will really work. Is there any way to pass parameters in this as well? That will really be helpful.

Guy Over a year ago

@PranjalDoshi There is, see updated answer.

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