Why a variable function can be called from a array in php?

Question

I am reading the documentation of php about Variable functions

I don't understand the example 4 below.

How come the first and second $func(); can call the function bar() and baz(). The $func is a array.

Maybe it is a silly question. Thanks.

<?php
class Foo
{
    static function bar()
    {
        echo "bar\n";
    }
    function baz()
    {
        echo "baz\n";
    }
}

$func = array("Foo", "bar");
$func(); // prints "bar"
$func = array(new Foo, "baz");
$func(); // prints "baz"
$func = "Foo::bar";
$func(); // prints "bar"
?>

Nico Haase · Accepted Answer · 2021-07-22 14:58:04Z

2

Have a look at the documentation of callables - if an array is used, the first element references the class name to be used, the second element references the method name to be called. This means, the two last lines are equal:

$func = array("Foo", "bar");

$func(); // prints "bar"
Foo::bar(); // also prints "bar"

answered Jul 22, 2021 at 14:58

Nico Haase

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1 Comment

ikhvjs Over a year ago

Thanks, it would be better if the callables are mentioned in the vairable functions example as a reference. Also, the callables documentation doesn't have examples like $func().

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