Split a string in an array of strings in c

Question

I am trying to split a string based on a given char, in this case ' ' and assign each word to an array of strings and print out each element of the array.

So far, I am able to get each word of the string except for the last one :(

How do I get the last word?

code:

#include <stdio.h>
#include <string.h>

int main()
{
    char    str[101] = "Hello my name is balou";
    char    temp[101];
    char    arr[10001][101];
    int     count;
    int     i;
    int     j;

    count = 0;
    i = 0;
    j = 0;
    while (str[i] != '\0')
    {
        if (str[i] == ' ' || str[i] == '\n')
        {
            strcpy(arr[count], temp);
            memset(temp, 0, 101);
            count += 1;
            j = 0;
            i++;
        }
        temp[j] = str[i];
        i++;
        j++;

    }

    i = 0;
    while (i < count)
    {
        printf("arr[i]: %s\n", arr[i]);
        i++;
    }
    return (0);
}

output:

arr[i]: Hello
arr[i]: my
arr[i]: name
arr[i]: is

As for your problem, you need an extra strcpy call after the splitting loop to get the last part. — Some programmer dude
– Some programmer dude, Commented Oct 1, 2021 at 11:40
memset(temp, 0, 101) should also be called before you enter the while loop. And BTW it should be memset(temp, 0, sizeof(temp)), in case you change the size of temp. — Jabberwocky
– Jabberwocky, Commented Oct 1, 2021 at 11:41

4386427 · Accepted Answer · 2021-10-01 11:50:06Z

2

Since you do:

while (str[i] != '\0')

you won't do any strcpy of the last word.

You can add

strcpy(arr[count], temp);
count += 1;

just after the while

But...

Notice that your current code has a number of problems. For instance double spaces, strings ending with a space, strings starting with a space, etc.

Further do

char    temp[101];  -->   char    temp[101] = { 0 };

and also add some code to ensure that j never exceeds 100

and... the size of char arr[10001][101]; may be too big as a variable with automatic storage duration on some systems.

And

printf("arr[i]: %s\n", arr[i]); --> printf("arr[%d]: %s\n", i, arr[i]);

edited Oct 1, 2021 at 11:50

answered Oct 1, 2021 at 11:40

4386427

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1 Comment

Balou Over a year ago

Awesome ^^ thx a bunch

Jaguar Nation · Accepted Answer · 2021-10-02 01:13:35Z

Research string token strtok function and accessing values pointed by array of pointers.
strtok()
array of pointers

#include <string.h>
#include <stdio.h>

int main () 
{
  char str[80] = "Hello my name is balou";
  const char s[2] = " "; //delimiter
  char *token; 
  char *words[5]; //store words
  int i = 0;
  
  /* get the first token */
  token = strtok(str, s);
  
  /* walk through other tokens */
  while( token != NULL )
  {
    words[i++] = token;
   
    token = strtok(NULL, s);
  }
  
  int r, c;
  
  // print words
  for (r = 0; r < 5; r++)
  {
    c = 0;
    while(*(words[r] + c) != '\0')
    {
      printf("%c", *(words[r] + c));
      c++;
    }
    printf("\n");
  }
  
  return(0);
}

OUTPUT:

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