which method c do this? thanks
for example, a string [] = "abc";
a array[4];
array[0] = 'a';
array[1] = 'b';
array[2] = 'c';
thanks
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6 Answers
Why don't you just subscript it...
int main() {
char *str = "hello";
printf("%c", str[0]); // h
return 0;
}
You can also use array syntax to define the string char str[] = "hello".
Update
#include <string.h>
#include <stdio.h>
int main() {
char str[] = "hello";
int i;
int strLength = strlen(str);
for (i = 0; i < strLength; i++) {
printf("[%c]", str[i]);
}
return 0;
}
Output
[h][e][l][l][o]
A string in C is actually an array of characters so you don't have to do anything.
retrieve it like so
char *string = "abcdef";
for (int i = 0; i < 7; ++i) {
printf("%c\n", string[i]);
}
1 Comment
Jim Balter
There's no C++ tag here so please don't post C++ code as an answer.
Try this:
char variable[] = "abc";
Comments
Consider using the function memcpy.
answered Mar 7, 2011 at 5:58
Shamim Hafiz - MSFT
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Comments
In C you don't have any specific type for string. String is a char * and points to the start of the string. Each string ends with a null character. So, you can directly use your string (char *) variable as an array but stop one character short of its strlen
Comments
A string in C is itself an array use the following:
char yourarray[] = "asldkjsl";
each character is an array you can access them as yourarray[0], yourarray[1]
