pass value from object to another object in javascript

Question

const small = {
  a: 1,
  func: function(b, c, d) {
    return this.a + b + c + d;
  },
};

const large = {
  a: 5,
};

small.func(2, 3, 5);

I need to access a: 5 from large object into small object. currently small.func(2,3,5) is giving 11 as output. I need to get 15 as ouput.

better to put the method outside of the object and then call it for any object you create. — Shiju Nambiar
– Shiju Nambiar, Commented Jan 15, 2022 at 5:10

Shiju Nambiar · Accepted Answer · 2022-01-15 05:14:06Z

1

Like this-

function func(b, c, d) {
    return this.a + b + c + d;
  }
const small = {
  a: 1,
  
};

const large = {
  a: 5,
};

func.call(large, 2,3, 5)

answered Jan 15, 2022 at 5:14

Shiju Nambiar

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Comments

DecPK · Accepted Answer · 2022-01-15 05:09:08Z

1

You can either use call or apply here as:

const result = small.func.call(large, 2, 3, 5);

What above statement means is that You are taking the function(or can say borrowing) small.func function and applying in the context of large object with argument 2, 3, 5.

const small = {
  a: 1,
  func: function(b, c, d) {
    return this.a + b + c + d;
  },
};

const large = {
  a: 5,
};

   const result = small.func.call(large, 2, 3, 5);
// const result = small.func.apply(large, [2, 3, 5]);
console.log(result);

answered Jan 15, 2022 at 5:09

DecPK

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