Separate list of objects in Python

Question

I need to separate a list of objects in Python but I don't know how to do and don't found the solution.

My list is 244 cells of data like that :

{'x':-9.717017,'y':-14.0228567,'z':145.401215}

and I want, as a result, 3 lists with all the 'x', all the 'y' and all the 'z'. The original list is express as :

['{'x':-9.717017,'y':-14.0228567,'z':145.401215}', ... , '{'x':-6.44751644,'y':-65.20397,'z':-67.7079239}'].

Thanks a lot.

What have you tried? This is not hard. x = [d['x'] for d in data]. — Tim Roberts
– Tim Roberts, Commented Jul 5, 2022 at 20:36
Do you really have quotes around each dictionary in the original list? — Barmar
– Barmar, Commented Jul 5, 2022 at 20:39
I already try this but there is quotation mark at each cell so it return an error message : TypeError: string indices must be integers. Not just next to the x, y and z. — Lucas Monnier
– Lucas Monnier, Commented Jul 5, 2022 at 20:51

Barmar · Accepted Answer · 2022-07-05 20:42:15Z

1

Loop over the list, and call ast.literal_eval() to convert each string to a dictionary. Then append each item in the dictionary to the appropriate list.

import ast

x_list = []
y_list = []
z_list = []
for item in data:
    d = ast.literal_eval(item)
    x_list.append(d['x'])
    y_list.append(d['y'])
    z_list.append(d['z'])

answered Jul 5, 2022 at 20:42

Barmar

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Aditya · Accepted Answer · 2022-07-05 20:40:30Z

0

You can return the 'x', 'y', 'z' components while iterating over your list of dict() elements.

E.g.,

data = [{'x':-9.717017,'y':-14.0228567,'z':145.401215}, {'x':-9.717017,'y':-14.0228567,'z':145.401215}]

x = [d['x'] for d in data]
y = [d['y'] for d in data]
z = [d['z'] for d in data]

This should return the individual lists in x, y, and z respectively.

answered Jul 5, 2022 at 20:40

Aditya

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3 Comments

Lucas Monnier Over a year ago

There is quotation mark at each cell and this is my big difficulty. I try your code but it doesn't work, sadly.

user47 Over a year ago

In OP's data, each list item is actually wrapped with ', thus they are strings so cannot treat them like dicts.

Aditya Over a year ago

Oh, seems like I missed those parts.

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