Create list from objects in Python

Question

I'm having troubles creating a list from the numbers I made using my code.

ListA = [5,1,3,8,4]

LengthB = (len(ListA))


obj0 = ListA[0]
obj1 = ListA[1]
obj2 = ListA[2]
obj3 = ListA[3]
obj4 = ListA[4]

obj01 = int(obj0)
obj11 = int(obj1)
obj21 = int(obj2)
obj31 = int(obj3)
obj41 = int(obj4)

obj010 = obj01+obj11
obj110 = obj01+obj11+obj21
obj210 = obj11+obj21+obj31
obj310 = obj21+obj31+obj41
obj410 = obj31+obj41

ListBnum0 = (obj010 / 2)
ListBnum1 = obj110 / 3
ListBnum2 = obj210 / 3
ListBnum3 = obj310/ 3
ListBnum4 = obj410 / 2


print(ListBnum0)
print(ListBnum1)
print(ListBnum2)
print(ListBnum3)
print(ListBnum4)

FinalForm1 = str(ListBnum0)
FinalForm2 = str(ListBnum1)
FinalForm3 = str(ListBnum2)
FinalForm4 = str(ListBnum3)
FinalForm5 = str(ListBnum4)

Basically this program takes the ListA numbers and computes the average of the one behind the number, the number and number after if applicable. My real question is how can I take either ListBnum(0) to ListBnum(4) and create another list out of the numbers?

Why does this return an error below?

ListB = list[ListBnum0,ListBnum1,ListBnum2,ListBnum3,ListBnum4]

abarnert · Accepted Answer · 2013-10-04 23:41:24Z

4

The direct answer to your question is:

new_list = [ListBnum0, ListBnum1, ListBnum2, ListBnum3, ListBnum4]

The reason you get an error when doing this:

ListB = list[ListBnum0,ListBnum1,ListBnum2,ListBnum3,ListBnum4]

… is that list is a function, and function calls need parentheses to call them. You could write it like this:

ListB = list([ListBnum0,ListBnum1,ListBnum2,ListBnum3,ListBnum4])

However, there's no reason to do so. What the list function does is to take any iterable as an argument, and return a list with the same values. But [ListBnum0, …] is already a list, so you're just making a copy for no reason.

Meanwhile, this whole design is clunky. Better to process the whole list at a time, than to split it into 5 separate variables and process them one by one and merge them back into a list. For example:

ListA = [5,1,3,8,4]
List0 = [int(i) for i in ListA]
def avg(x):
    return sum(x) / len(x)
ListB = [avg(List0[max(i-1, 0):i+2]) for i in range(len(List0))]
ListFinal = [str(i) for i in ListB]

edited Oct 4, 2013 at 23:41

answered Oct 4, 2013 at 23:36

abarnert

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2 Comments

iratemaniac Over a year ago

yeah i know this was very sloppy to do but it made it easier for getting my result since this is the best way i could break it down in my head. im planning on redoing the list, but if i cant remake the program right i want a default to ensure i have the right answer. Thanks for the answer!

iratemaniac Over a year ago

Also how would you change the design to process it all at once?

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