Can someone tell me what the condition is in this php statement?
return $node->type == 'article' ? mymodule_page_article($node) : mymodule_page_story($node);
I'm sorry if this is not the place to ask such a simple question but I'm finding it difficult to look up specific code structure (especially when I don't know the name of it).
This is a ternary operator.
It's equivalent to
if( $node->type == 'article' ) {
return mymodule_page_article($node);
} else {
return mymodule_page_story($node);
}
What it does is: if the stuff before the ? is true, return the result of the expression in the first clause (the stuff between ? and :). If it's false, then it returns the result of the second clause (the stuff after the :).
This is the ternary operator ?: and can be expanded as follows:
if ($node->type == 'article') {
return mymodule_page_article($node);
} else {
return mymodule_page_story($node);
}
This is equivalent to:
if($node->type == 'article')
{
return mymodule_page_article($node);
}
else
{
return mymodule_page_story($node);
}
This is called the ternary operator. See the section on it here for more information: http://www.php.net/operators.comparison
this is a ternary expression.
the condition is $node->type == 'article' and if it's true it does mymodule_page_article($node) else mymodule_page_story($node)
If type of node is equal to 'article' do mymodule_page_article($node), if it isn't equal then do mymodule_page_story($node)
Use Ternary operator
return isset($node->type == 'article') ? mymodule_page_article($node) : mymodule_page_story($node)
