typedef int (*t_built)(t_cmds *, t_table *);
struct cmdline
{
char * reserved[7]; /* "echo pwd cd unset export exit env" */
t_built builtin[7];
}
How can I store my builtin functions into builtin array with same indexes as in reserved array. Can you help me to understand how this syntax works and for what declared typedef for function pointer.
Let's decompose the declarations:
int f(int);
declares f as a function taking an int and returning an int.
This can be written with parentheses (this is useless here but harmless):
int (f)(int);
The following declaration:
int *f(int);
declares f as a function taking an int and returning a pointer to an int.
This time, parentheses change the order of evaluation:
int (*f)(int);
declares f as a pointer to a function taking an int and returning an int.
typedef is used to define a type instead of a variable.
Finally the sequence:
typedef int (*f)(int);
f a[7];
declares a as an array of seven elements of type f, f describing a pointer to a function taking an int and returning an int.
By the way, there is a converter for that sort of things: cdecl: C gibberish ↔ English.
typedef-ed.typedef int t_build(t_cmds*, t_table*); t_build *builtin[7];.