How to declare an array of function pointers without using a typedef for the function pointer?

Question

I was demonstrating to a learning colleague how to use function pointers and how he could have an array of them. I put down the following code so that he could do indexed dispatch:

typedef void (*VoidFunction)();
VoidFunction functions[]  =
    {editProgramName,
     editProgramLength,
     editProgramCycles,
     editProgramNumberOfSets,
     editProgramEditSets,
     editProgramSave,
     editProgramCancel};
// now dispatch                    
functions[scroll.arrayFocusIndex]();

And then he asked... "How do I do it without the typedef?" To which I found after trying various things that seemed like they might work, I didn't have a clue to do. All the google hits I found always seemed to use a typedef. Is there a way to do it inline without the typedef of the function pointer?

@JerryCoffin You're quick. I was going to post that. (May I still do it?) — user529758
– user529758, Commented Dec 6, 2012 at 23:16

phonetagger · Accepted Answer · 2012-12-06 23:21:20Z

4

void (*functions[])() =
    {editProgramName,
     editProgramLength,
     editProgramCycles,
     editProgramNumberOfSets,
     editProgramEditSets,
     editProgramSave,
     editProgramCancel};
// now dispatch
functions[scroll.arrayFocusIndex]();

answered Dec 6, 2012 at 23:21

phonetagger

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2 Comments

phonetagger Over a year ago

Dammit, I started testing this before Jerry Coffin posted his comment. Honest.

Travis Griggs Over a year ago

Could have sworn that was one of the darts I threw at it, but apparently not. Seems obvious when I look at it now. Thank you so much!

user529758 · Accepted Answer · 2012-12-06 23:17:11Z

3

This has worked for me:

void a()
{
}

void b()
{
}

void (*functions[2])();

int main()
{
    functions[0] = a;
    functions[1] = b;
    return 0;
}

answered Dec 6, 2012 at 23:17

user529758

5 Comments

user529758 Over a year ago

@GManNickG Why delete your answer? It was good. But thanks anyway :)

GManNickG Over a year ago

Your first comment to Jerry was 3 second earlier than my answer. :) So I'm concluding you saw the question first.

user529758 Over a year ago

@GManNickG Maybe yes. Who knows :)

Travis Griggs Over a year ago

Gave you both an upvote to try and even things out a little. :)

phonetagger Over a year ago

@H2CO3 - What was your answer?

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