Variables in shell_exec() script

Question

Is there any possible way to make this simple script function properly?

<?php
$hi = "echo hi";
shell_exec($hi);
echo "<pre>$output</pre>";
?>

please help me out?

shouldn't shell_exec($hi); read $output = shell_exec($hi);? — DaveRandom
– DaveRandom, Commented Oct 17, 2011 at 23:15
thx, i must have accidentally deleted something, thats what i had originally — Trevor Rudolph
– Trevor Rudolph, Commented Oct 17, 2011 at 23:36

Allan MacGregor · Accepted Answer · 2011-10-17 23:15:58Z

3

Sure just assign the variable.

<?php
$hi = "echo hi";
$output = shell_exec($hi);
echo "<pre>$output</pre>";
?>

answered Oct 17, 2011 at 23:15

Allan MacGregor

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Comments

sidyll · Accepted Answer · 2011-10-17 23:15:27Z

1

$hi = "echo hi";
# the result needs to be assigned to $output before using it
$output = shell_exec($hi);
echo "<pre>$output</pre>";

answered Oct 17, 2011 at 23:15

sidyll

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