passing text variable using shell_exec

Question

I try to passing text using shell_exec.

$message="I go to school";

shell_exec("nohup php -q sendmail.php $picture $message");

but I get only the one word of message when I user argv[2]. what the problem?

nospor · Accepted Answer · 2016-10-11 12:41:37Z

4

You must add " for text

shell_exec("nohup php -q sendmail.php $picture \"$message\"");

answered Oct 11, 2016 at 12:41

nospor

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1 Comment

It is hard to believe ;) Show me your code after changes, make sure you are running proper script and show code how you get this data