Splitting a String in Java throws PatternSyntaxException

Question

I want to split a String in Android using Java. I have done this before but now I get this exception

11-20 17:57:37.665: ERROR/AndroidRuntime(25423): java.util.regex.PatternSyntaxException: Syntax error U_REGEX_MISMATCHED_PAREN near index 1:
11-20 17:57:37.665: ERROR/AndroidRuntime(25423): (
11-20 17:57:37.665: ERROR/AndroidRuntime(25423):  ^

My string is like

String mystring=  "iamhere(32)";

and I want to keep only the "iamhere".

I split it using

String[] seperation = mystring.Split("(");

What am I doing wrong?

I get an error when i use ("(") i tried using ("\(") and got it right :) — user878813
– user878813, Commented Nov 20, 2011 at 16:08
@user: java considers " ( "this as part of regular expression. try to use backslash to escape example : mystring.split("\("); — Dead Programmer
– Dead Programmer, Commented Nov 20, 2011 at 16:12

AndroGeek · Accepted Answer · 2012-05-15 05:51:01Z

7

("\(") would be an invalid escape sequence. To escape the meaning of "(" we should be using "\\" in java.

    String mystring = "iamhere(32)";
    String[] sep = mystring.split("\\(");
    System.out.println("String after split ",sep[0]+" ");

answered May 15, 2012 at 5:51

AndroGeek

1,3003 gold badges13 silver badges25 bronze badges

Sign up to request clarification or add additional context in comments.

Collectives™ on Stack Overflow

Splitting a String in Java throws PatternSyntaxException

1 Answer 1

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Related