How split a string using regex pattern

Question

How split a [0] like words from string using regex pattern.0 can replace any integer number. I used regex pattern,

private static final String REGEX = "[\\d]";

But it returns string with [.

Spliting Code

Pattern p=Pattern.compile(REGEX);
String items[] = p.split(lure_value_save[0]);

@JavaDevil i am using Pattern p=Pattern.compile(REGEX); String items[]=p.split(lure_value_save[0]); — user2251725
– user2251725, Commented Jul 12, 2013 at 13:58
Why not splitting by comma? List<String> list = Arrays.asList(str.split(",")); — Roger Rapid
– Roger Rapid, Commented Jul 12, 2013 at 13:59
@RogerRapid Sorry.here is little problem.String either contain [0] or [1].etc — user2251725
– user2251725, Commented Jul 12, 2013 at 14:32

jlordo · Accepted Answer · 2013-07-12 14:32:13Z

1

You have to escape the brackets:

String REGEX = "\\[\\d+\\]";

edited Jul 12, 2013 at 14:32

answered Jul 12, 2013 at 13:58

jlordo

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Comments

winne2 · Accepted Answer · 2013-07-12 14:12:02Z

1

Java doesn't offer an elegant solution to extract the numbers. This is the way to go:

Pattern p = Pattern.compile(REGEX);

String test = "[0],[1],[2]";
Matcher m = p.matcher(test);

List<String> matches = new ArrayList<String>();     
while (m.find()) {
    matches.add(m.group());
}

answered Jul 12, 2013 at 14:12

winne2

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