Convert Hex String to unsigned Byte Array in Java

Question

I get hex strings of 14 bytes, e.g. a55a0b05000000000022366420ec. I use javax.xml.bind.DatatypeConverter.parseHexBinary(String s) to get an array of 14 bytes. Unfortunately those are unsigend bytes like the last one 0xEC = 236 for example.

But I would like to compare them to bytes like this: if(byteArray[13] == 0xec) Since 235 is bigger than a signed byte this if statement would fail. Any idea how to solve this in java? Thx!

Treat it as an unsigned byte and comparison is the same.

Peter Lawrey
– Peter Lawrey

2011-12-08 14:53:31 +00:00
Commented Dec 8, 2011 at 14:53 — Peter Lawrey
– Peter Lawrey, Commented Dec 8, 2011 at 14:53

korifey · Accepted Answer · 2011-12-08 14:52:14Z

9

Try if(byteArray[13] == (byte)0xec)

answered Dec 8, 2011 at 14:52

korifey

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MByD · Accepted Answer · 2011-12-08 14:54:24Z

3

You can promote the byte to integer:

if((byteArray[13] & 0xff) == 0xec)

answered Dec 8, 2011 at 14:54

MByD

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Anantha Sharma · Accepted Answer · 2011-12-08 15:54:12Z

0

since java doesn't support (atleast with primitives) any unsigned data types, you should look at using int as your data type to parse the string..

        String str = "a55a0b05000000000022366420ec";
        int[] arrayOfValues = new int[str.length() / 2];
        int counter = 0;
        for (int i = 0; i < str.length(); i += 2) {
            String s = str.substring(i, i + 2);
            arrayOfValues[counter] = Integer.parseInt(s, 16);
            counter++;
        }

work with the arrayOfValues...

answered Dec 8, 2011 at 15:54

Anantha Sharma

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