I get hex strings of 14 bytes, e.g. a55a0b05000000000022366420ec.
I use javax.xml.bind.DatatypeConverter.parseHexBinary(String s) to get an array of 14 bytes.
Unfortunately those are unsigend bytes like the last one 0xEC = 236 for example.
But I would like to compare them to bytes like this:
if(byteArray[13] == 0xec)
Since 235 is bigger than a signed byte this if statement would fail.
Any idea how to solve this in java?
Thx!
Try if(byteArray[13] == (byte)0xec)
You can promote the byte to integer:
if((byteArray[13] & 0xff) == 0xec)
since java doesn't support (atleast with primitives) any unsigned data types, you should look at using int as your data type to parse the string..
String str = "a55a0b05000000000022366420ec";
int[] arrayOfValues = new int[str.length() / 2];
int counter = 0;
for (int i = 0; i < str.length(); i += 2) {
String s = str.substring(i, i + 2);
arrayOfValues[counter] = Integer.parseInt(s, 16);
counter++;
}
work with the arrayOfValues...
