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I'm in the process of making a bash script to automate adding a user. My password always have pattern, so I am setting that to a variable then... (this is where I am stuck -encrypting-). I found this post but that talks about -stdin which I don't want to use. Besides, I am asked for the password if I omit it anyway. So, how can I encrypt the password from my username automatically?

My script

#!/bin/bash
if [ $# -ne 1 ]
then
  echo "Usage: $0 <user>"
else
  p=${1%.*}
  p=$(echo $p | tr -d 'aeiou' | openssl passwd) $1
  useradd -p $p $1
fi

EDIT: mkpasswd on CentOS doesn't seem to work like the one mentioned in the post I linked.

EDIT2: bash version is 4.1.2(1)-release, if that matters.

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2 Answers 2

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2

You can use useradd and chpasswd to automate user creation. e.g.

useradd -c "Bob Smith" -m bob
echo "bob:mypassword" | chpasswd

If you don't want the plain text password to appear in the script, use the --encrypted flag:

echo "bob:encrypted_mypassword" | chpasswd --encrypted
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  • I have a pattern when creating the password, so I'd rather stick to that. With that said, maybe it's time to lose the pattern and use standard stuff. Commented May 14, 2015 at 8:34
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I ended up using this, inspired from this post

#!/bin/bash
if [ $# -ne 1 ]
then
  echo "Usage: $0 <user>"
else
  u=${2%.*}
  u=${u//[aeiou]}
  echo "$2:$u" > .tmp
  useradd $2
  < .tmp chpasswd
fi
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