awk for loop with leading zeros in variable

Question

I want to run a for loop in awk with leading zeros in the index variable.

This isn't for printing a number with leading zeros, which I could easily handle with a printf statement. It's for checking if the given number (with leading zeros) has been used as an index in an array.

So what I actually want is to iterate through string values in awk, from "01" to "14" (or whatever).

Something like:

myarray["01"]
myarray["02"]
myarray["04"]
myarray["05"]
# ... etc, up to "12"

for (i = 01; i <= 12; i++) {
  if (! (i in myarray)) {
    print i " is missing from myarray"
  }
}

Should report that "03 is missing from myarray." But that's not how it works.

How can I do this?

cuonglm · Accepted Answer · 2016-01-12 03:33:21Z

4

Just use sprintf:

BEGIN {
  myarray["01"]
  myarray["02"]
  myarray["04"]
  myarray["05"]
  # ... etc, up to "12"

  for (i = 1; i <= 12; i++) {
    k = sprintf("%02d", i)
    if (! (k in myarray)) {
      print k " is missing from myarray"
    }
  }
}

gave you:

03 is missing from myarray
06 is missing from myarray
07 is missing from myarray
08 is missing from myarray
09 is missing from myarray
10 is missing from myarray
11 is missing from myarray
12 is missing from myarray

answered Jan 12, 2016 at 3:33

cuonglm

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