I am trying to use an argument of the script to find other files. The problem is that when i give the script the argument x.* in the command line, it is transformed into x.sh. Any ideas how i can get the x.* inside my script?
The script in comand line : ./script.sh x.*.
If i try to print $1 it outputs x.sh.
You can't do it from the inside of your script. * has to be escaped, otherwise it will try to fit filenames (in your case x., then anything, as * is a glob operator that matches any string in filename). You can do it in, basically, three ways - enclose your string with single or double quotes:
./script.sh "x.*"
./script.sh 'x.*'
Or prefix problematic character with backslash:
./script.sh x.\*
As Jeff mentioned in the comments (thanks), you can also disable glob expansion with:
set -o noglob
You can turn it back on with set +o noglob if you want to.
shopt. Will edit the answer accordingly, thanks.
*. So, you show 'x.*' and x.\* but you are missing "x.*". That's three ways.