Under Arch USB iso, zsh, running the script ./test containing :
#!/bin/bash
PATH=$(dirname $0)
ls $PATH
returns
ls: command not found
Any idea how to fix this ?
EDIT : ls alone works but not when I'm adding $PATH
Edit : just realized from the comments that $PATH is an environment variable and I was replacing its value...
The variable PATH is a special one. There are a lot of special variables (and all are all capital, so easily avoided). PATH holds a list of directories to search for commands.
For fun and learning (though these are the same thing), type echo $PATH, outside of script, to see what it has in it.
To fix problem do not break PATH: use a different variable name (not all capitals).
Try /bin/ls, it seems that ls is not in the path as @123 has mentioned in the comment.
To add /bin to the PATH. Add in ~/.bashrc
export $PATH=$PATH:/bin
export command wrong (expects a variable name to the left of =, not a variable expansion), this does not take into account that the user is using PATH as an ordinary variable.
Try:
#!/bin/bash
PATH="$PATH:$(dirname $0)"
ls $PATH
This way you're adding $(dirname $0) to the PATH variable instead of replacing it. Or, if you don't want to edit the environment variable and want to use $(dirname $0) separately, use a different variable name.
PATH as a variable holding the script's directory and then wants to view the contents of that directory with ls. Adding the directory to the end of the PATH variable would be correct if they want to access executables in that directory without using their absolute path (there is no indication that this is what they want), but listing the $PATH value with ls is nonsensical.
echo $PATHin your script. If it doesn't contain/binthen add it.*to list files of the current directory so you can always doecho .* *