I've an array coming from the output of a command:
array=(saf sri trip tata strokes)
Now I want to filter items based on user input. The user can also use wildcards, so if the user enters *tr*, the output should be
trip strokes
2 Answers
It's easier with zsh:
$ array=(saf sri trip tata strokes)
$ pattern='*tr*'
$ printf '%s\n' ${(M)array:#$~pattern}
trip
strokes
${array:#pattern}: expands to the elements of the array that don't match the pattern.(M)(for match): reverts the meaning of the:#operator to expand to the elements that match instead$~pattern, causes the content of$patternto be taken as a pattern.
answered Dec 7, 2016 at 16:22
Stéphane Chazelas
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On
GNU bash, version 5.1.4(1)-release (x86_64-pc-linux-gnu)I get this error:${(M)array:#$~pattern}: bad substitutionXaqron– Xaqron2021-03-15 09:35:29 +00:00Commented Mar 15, 2021 at 9:35 -
1@Xaqron, GNU
bashis notzsh.Stéphane Chazelas– Stéphane Chazelas2021-03-15 09:36:14 +00:00Commented Mar 15, 2021 at 9:36
One way to do it:
array=(saf sri trip tata strokes)
input=*tr*
for foo in "${array[@]}"; do
case "$foo" in
$input) printf '%s\n' "$foo" ;;
esac
done
Note to the overly enthusiastic quoters: the right-hand side in assignments (such as *tr* in input=*tr*) doesn't need quoting.
trwith no wildcard? Nothing?