I'm new in Linux and I also know this is a pretty common problem in the forum's questions but I have tried several options and I can't solve this issue. I am trying to execute the following script:
!/bin/bash
for i in {1..10}
do
asreml -r2 Prueba_"$i".as > stdout_"$i".txt &&
done
But I got the following error message:
bash: ./jobs1-2.sh: line 9: syntax error near unexpected token `done'
bash: ./jobs1-2.sh: line 9: `done'
I will appreciate any help
Indeed, as the commenters have shown, you have a syntax error inside the loop, which confused bash when it tried to find the end of the loop.
You probably meant to either:
chain a second command after asreml that would run if asreml finished successfully ($? == 0); for example: asreml -r2 Prueba_"$i".as > stdout_"$i".txt && echo asreml finished successfully or
put the asreml command into the background: asreml -r2 Prueba_"$i".as > stdout_"$i".txt &
; either. And yes, this will start the next even if the previous one fails. If you don't want that, use asreml -r2 . . . || exit. But this should be in a new question. Also, since Jeff answered your question, please take a moment and accept it by clicking on the check mark to the left. That will mark the question as answered and is the way thanks are expressed on the Stack Exchange sites.
&& and || to decide when to execute a second command based on the success of the first one.
&&&&by;&.&&connects two commands, and you did not provide one on the right-hand side. See Lists in the manual: gnu.org/software/bash/manual/bashref.html#Lists