multiple commands in sed with xargs input

Question

I've a file ./123bar/foo.txt which has:

pro := text
ver := 1.0
rev := 2

and two env variables:

var =2.1
var2=3

I want to replace all ver with $var and rev with $var2. Expected output:

pro := text
ver := 2.1
rev := 3

I'm trying below to first find all the files with find and grep and then pass it to sed to achieve the result. Below is the command I'm running:

find . -name 'foo.txt' | grep -P "\/[0-9]{3}bar" | xargs -I{} sed -E "s/:= *[0-9]+\.[0-9]+ *$/:= $var/g" -E "s/:= [0-9]+ *$/:= $var2/g" {}

it's not working and giving me error:

sed: can't read s/:= [0-9]+ *$/:= 3/g: No such file or directory
pro := text
ver := 2.1
rev := 45

How do I fix it? A neater/simpler solution is also welcome.

Olorin · Accepted Answer · 2018-03-13 04:30:34Z

1

The option for using multiple expressions with sed is -e, not -E:

sed -e "s/:= *[0-9]+\.[0-9]+ *$/:= $var/g" -e "s/:= [0-9]+ *$/:= $var2/g"

From the manual (assuming GNU given the linux tag):

'-e SCRIPT'
'--expression=SCRIPT'
Add the commands in SCRIPT to the set of commands to be run while processing the input.

-E is for using extended regular expressions.

answered Mar 13, 2018 at 4:30

Olorin

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got it but the above command not working. adding -E in the beginning worked though: sed -E -e "s/:= *[0-9]+\.[0-9]+ *$/:= $var/g" -e "s/:= [0-9]+ *$/:= $var2/g". thanks for pointing out though.

helix
– helix

2018-03-13 04:48:44 +00:00
Commented Mar 13, 2018 at 4:48
@helix ah, I see, you're using +, which does need -E. I didn't notice that at first. If you use \+ instead, though, you won't need the -E.

Olorin
– Olorin

2018-03-13 04:54:01 +00:00
Commented Mar 13, 2018 at 4:54

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