Parsing out number from URL in bash and feeding into another bash function?

Question

https://github.com/org/repo/pull/777

I'm trying to parse out the last number of this url in bash function 1 and pass that result into bash function 2.

I have this elementary example I have been playing with:

  1 pullpr() {
  2         git checkout pr/$1
  3 }
  4
  5 co() {
  6         pullpr awk -F/ '{print $7}' <<<$1
  7 }

I can't seem to get this to work, but I'm wanting to do this correct way.

Stéphane Chazelas · Accepted Answer · 2018-08-24 15:23:34Z

5

You can use the shell’s parameter expansion features to extract the number:

url=https://github.com/org/repo/pull/777
echo "${url##*/}"

This will also work with positional parameters:

set https://github.com/org/repo/pull/777
echo "${1##*/}"

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answered Aug 24, 2018 at 14:51

Stephen Kitt

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