How to print a specific variable from a command's output using grep

Question

test.txt file:

Ext Temperatur:  210.0°
Avg.Speed(All):    62.89mm/s
Avg.Speed(Print):  49.99mm/s
Avg.Speed(Travel): 199.84mm/s
Overall Time (w/o Acceleration): 11:00:41 (39640.65sec)

How can I grab 39640.65sec and 39640.65 as outputs using grep and print with php code?

I am using this code but it prints e.g.: 11:00:41 (39640.65sec)

<?php
$gcode_new = "grep -Po '(?<=Overall Time \(w/o Acceleration\):   ).*' test.txt";

include('Net/SSH2.php');

$ssh = new Net_SSH2('XXX.61.XXX.227');
if (!$ssh->login('root', 'PASS')) {
    exit('Login Failed');
}
$target = $ssh->exec($gcode_new);

echo $target ;
?>

You seem to ask a question about each individual number in that particular data. It would be better if you had asked how to get them all, or tried to give an overview of what it is that you're actually trying to do, and what significance the PHP code plays and why we need to see that in each and every question. — Kusalananda
– Kusalananda ♦, Commented Apr 16, 2020 at 7:55

schrodingerscatcuriosity · Accepted Answer · 2020-04-16 05:41:58Z

2

You can try this:

grep -Po "[.0-9]*(?=sec\))"

Output:

39640.65

answered Apr 16, 2020 at 5:41

schrodingerscatcuriosity

12.8k5 gold badges38 silver badges64 bronze badges

If we have two outputs which sends with"sec" how can i select particular line. For eg: Overall Time (w/o Acceleration): 11:00:41 (39640.65sec) Overall Time (w/ Acceleration): 6:16:31 (22591.3sec) How to select only 39640.65

testcod
– testcod

2020-04-16 06:40:45 +00:00
Commented Apr 16, 2020 at 6:40

Add a comment |

Stalin Vignesh Kumar · Accepted Answer · 2020-04-16 07:29:29Z

1

If mutiple lines occur in file :

Use this to get the first occurrence in the file :

grep -m1 -Po "[.0-9]*(?=sec\))" testing.txt

To get the last occurrence in the file :

grep -Po "[.0-9]*(?=sec\))" testing.txt | tail -1

answered Apr 16, 2020 at 7:29

Stalin Vignesh Kumar

1,8058 silver badges15 bronze badges

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