Suppose I have bash_functions.sh:
function test(){
}
function test2(){
}
And in my ~/.bashrc I do:
source ~/bash_functions.sh
Is it possible to, when sourcing it, avoid sourcing a specific function? I mean, source everything in bash_functions.sh, except for test?
In a function definition foo () { … }, if foo is an alias, it is expanded. This can sometimes be a problem, but here it helps. Alias foo to some other name before sourcing the file, and you'll be defining a different function. In bash, alias expansion is off by default in non-interactive shells, so you need to turn it on with shopt -s expand_aliases.
If sourced.sh contains
foo () {
echo "foo from sourced.sh"
}
then you use it this way
foo () {
echo "old foo"
}
shopt -s expand_aliases # necessary in bash; just skip in ash/ksh/zsh
alias foo=do_not_define_foo
. sourced.sh
unalias foo; unset -f do_not_define_foo
foo
then you get old foo. Note that the sourced file must use the foo () { … } function definition syntax, not function foo { … }, because the function keyword would block alias expansion.
foo () form and not in the ksh extension function foo form, but other than that you can effectively re-route any number of function definitions.
Not exactly, however, you can override the test() function. The last function definition always takes precedence. So if you source a file that has test() then define a function with the same name after that, the latter function will override the one that was sourced. I take advantage of this to provide some object-orientedness in some of my scripts.
Example:
bash_functions.sh:
test(){
echo "This is the test function from bash_functions."
}
test2(){
echo "This is the test2 function from bash_functions."
}
scripty_scripterson.sh
test2(){
#this is thrown in just to show what happens in
#the other direction
echo "This is the test2 function from scripty."
}
source bash_functions.sh
test1(){
echo "This is the test1 function from scripty."
}
test1
test2
At the command line:
$ ./scripty_scripterson.sh
This is the test1 function from scripty.
This is the test2 function from bash_functions.
You may create a temp-file, read it in, and delete it afterwards. To delete function 'test', I assume here that there is no '}' inside the function.
sed '/test()/,/}/d' testrc > ./tmprc && source ./tmprc && rm tmprc
That's not possible. You can divide bash_functions.sh into 2 file, one include what you want to source, and another include the functions you don't want to source. and use a 3rd script file to combine them for normal usage.
