Wordpress: PHP code rendering in the wrong place

Question

I'm trying to insert a php code for a post-rating on wordpress. It used to work out of the echo normally and in-place. Now, using this code, instead of the rating showing up after "User Rating:" it renders completely out of the 'anime-info' div and show up above it.

The code is " . the_ratings() . " The full code should be: but " . if(function_exists('the_ratings')) { the_ratings() } . " didn't work so I had to change it.

Here's the full code. Basically, if the category ID assigned to the current post is 4, it shows this text and an image. If it's not, it renders only a image.

Any suggestions?

This is the plugin I'm using http://wordpress.org/extend/plugins/wp-postratings/

Thanks!

    <?php foreach((get_the_category()) as $category)
            { if($category->cat_ID = 4){ echo "<div class='anime-info'>
                    <div class='anime-inf left'>
                    <b>Anime Title:</b> ".get_post_meta( $post->ID, 'anime_title', true )."<br />
                    <b>Creator:</b> ".get_post_meta( $post->ID, 'anime_creator', true )."<br />
                    <b>Genres:</b> ".the_tags()." <br />
                    <b>Studio:</b> ".get_post_meta( $post->ID, 'anime_studio', true )."<br />
                    <b>First aired at:</b> ".get_post_meta( $post->ID, 'anime_firstaired', true )."<br />
                    <b># of Episodes:</b> ".get_post_meta( $post->ID, 'anime_episodes', true )."<br />
                    <b>Official Website:</b> ".get_post_meta( $post->ID, 'anime_website', true )."<br />
                    <b>Anime ii Rating:</b> ".get_post_meta( $post->ID, 'anime_revrating', true )."<br /> <br />
                    <b>User Rating:</b>" .  the_ratings() . "
                    </div>
                    <div class='post-image-inner right'>
                       img src='".get_bloginfo( 'template_directory' )."/timthumb.php?src=".get_post_meta( $post->ID, 'image_value', true )."&amp;w=225&amp;h=246&amp;zc=1' />
                        </div>
                        </div>"; 
                }else{ echo "<div class='post-image'><img src='".get_bloginfo('template_directory')."/timthumb.php?src=".get_post_meta( $post->ID, 'image_value', true )."&amp;w=529&amp;h=253&amp;zc=1' /></div>";
                                    }
                                }
                        ?>

Milo · Accepted Answer · 2011-07-17 21:58:44Z

1

It's because you're echoing a function that itself echoes a value. The function has a display parameter that you have to set to false if you want it to return it's value to use it that way:

function the_ratings($start_tag = 'div', $custom_id = 0, $display = true)

Also -

if($category->cat_ID = 4)

should be:

if($category->cat_ID == 4)

answered Jul 17, 2011 at 21:58

Milo

79.1k4 gold badges128 silver badges172 bronze badges

1

To avoid this: if ( $category->cat_ID = 4 ), I would strongly recommend getting in the habit of "Yoda" casing your conditionals, i.e.: if ( 4 == $category->cat_ID ), which will return an error if = is mistakenly used in place of ==.

Chip Bennett
– Chip Bennett

2011-07-17 22:02:12 +00:00
Commented Jul 17, 2011 at 22:02
@Chip Bennett - ha, Yoda casing. good tip!

Milo
– Milo

2011-07-18 02:11:09 +00:00
Commented Jul 18, 2011 at 2:11

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Sean Lee · Accepted Answer · 2011-07-17 22:03:03Z

0

Just the_rating() will work.

Without looking at your generated page, not sure if it's styling problem. Make sure that this foreach code block is placed within <?php while (have_posts()) : the_post(); ?>

answered Jul 17, 2011 at 22:03

Sean Lee

1,1093 gold badges15 silver badges20 bronze badges

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