I am working with an array and need some help. I would like to create an array where the first field is a String type and the second field is an Integer type. For result:
Console out
a 1
b 2
c 3
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what have you tried? mattgemmell.com/2008/12/08/what-have-you-triedBogdan Emil Mariesan– Bogdan Emil Mariesan2012-04-04 08:47:09 +00:00Commented Apr 4, 2012 at 8:47
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Check this link stackoverflow.com/questions/4393027/…Harish N– Harish N2012-04-04 08:49:45 +00:00Commented Apr 4, 2012 at 8:49
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6 Answers
An array can only have a single type. You can create a new class like:
Class Foo{
String f1;
Integer f2;
}
Foo[] array=new Foo[10];
You might also be interested in using a map (it seems to me like you're trying to map strings to ids).
EDIT: You could also define your array of type Object but that's something i'd usually avoid.
Comments
You could create an array of type object and then when you print to the console you invoke the toString() of each element.
Object[] obj = new Object[]{"a", 1, "b", 2, "c", 3};
for (int i = 0; i < obj.length; i++)
{
System.out.print(obj[i].toString() + " ");
}
Will yield:
a 1 b 2 c 3
Comments
Object[] randArray = new Object [3];
randArray[0] = new Integer(5);
randArray[1] = "Five";
randArray[2] = new Double(5.0);
for(Object obj : randArray) {
System.out.println(obj.toString());
}
Is this what you're looking for?
Comments
Object[] myArray = new Object[]{"a", 1, "b", 2 ,"c" , 3};
for (Object element : myArray) {
System.out.println(element);
}
Comments
Object [] field = new Object[6];
field[0] = "a";
field[1] = 1;
field[2] = "b";
field[3] = 2;
field[4] = "c";
field[5] = 3;
for (Object o: field)
System.out.print(o);
3 Comments
Niraj Nawanit
@xmoex: The solution is okay except here the array is being initialized in crude way.
chalimartines
this Object[] myArray = new Object[]{"a", 1, "b", 2 ,"c" , 3}; is just syntactic sugar and for this question is my solution fine.
xmoex
no offense, but imho I'd consider this bad coding style as it ignores the pairwise occurrence of string and integer per item
try using Vector instead of Array.
1 Comment
Eric Tobias
This answer does not address the question in the slightest!