How use sql "like" in PyMongo?

Question

>>> db.houses.find().count()
11616
>>> db.houses.find({"hid":u"16999"}).count()
1
>>> db.houses.find({"hid":u"/9/"}).count()
0

The documentation says that sql "like" (SELECT * FROM users WHERE name LIKE "%Joe%") in MongoDB is db.users.find ({name:/Joe/}).

If you specify a query directly to the cli-client interface mongodb, then everything works correctly, but does not work in pymongo.

What is the problem?

Thanks.

georg · Accepted Answer · 2012-04-04 20:34:09Z

43

pymongo doesn't support regex literals, you have to use the '$regex' predicate:

 db.houses.find({"hid":{"$regex": u"9"}})

answered Apr 4, 2012 at 20:34

georg

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4 Comments

what is the syntax if 9 represented as variable(search_word)? db.houses.find({"hid":{"$regex": usearch_word}}) .... ???

@vogash: I guess, yes. Note that mongodb uses PCRE regexes, not python's.

it says that variable usearch_word is not defined

Any answer, can you send example of using parameter instead of hard coded 9