So I posted this question here.
And the solution works.. but i should have been more careful. Please take a look at the link above.
What if I dont have a lists explicitly as a,b,c,d but I have a list of lists.. something like
lists.append(a)
lists.append(b)
and so on. And in the end all i have is "lists"
This
for item in itertools.product(lists):
print(item)
doesnt work in this case??
Unpacking everything from a list using *:
>>> import itertools
>>> a = ["1"]
>>> b = ["0"]
>>> c = ["a","b","c"]
>>> d = ["d","e","f"]
>>> lists = [a,b,c,d]
>>> for item in itertools.product(*lists):
print item
('1', '0', 'a', 'd')
('1', '0', 'a', 'e')
('1', '0', 'a', 'f')
('1', '0', 'b', 'd')
('1', '0', 'b', 'e')
('1', '0', 'b', 'f')
('1', '0', 'c', 'd')
('1', '0', 'c', 'e')
('1', '0', 'c', 'f')
This just unpacks the list into its elements so it is the same as calling itertools.product(a,b,c,d). If you don't do this the itertools.product interperets it as one item, which is a list of lists, [a,b,c,d] when you want to be finding the product of the four elements inside the list.
@sberry posted this useful link: http://docs.python.org/tutorial/controlflow.html#unpacking-argument-lists
* does.