Php If multiple variables

Question

I'm trying to make a general if for some variables that i have in my database. Let's say that we have the next variables and values:

$var1 = "abc";
$var2 = "n/a";
$var3 = "das";
$var4 = "n/a";

My if statement must include all these variables, check which variables contain "n/a" and for every variable that contain "n/a" the script must make another variable $var21 = "Not Available". Is that possible?

you can set up a default value inside your database. Maybe it will do the trick — Deblaton Jean-Philippe
– Deblaton Jean-Philippe, Commented Apr 6, 2012 at 13:51

Chuck Callebs · Accepted Answer · 2012-04-06 14:32:02Z

1

I'd not use variable variables, just due to personal preference. If you're masochistic, you can certainly try.

I'd create an extra hash instead. ~~This would remove the need for an if-statement as well~~. :)

$descriptions = array(
    "n/a" => "Not Available",
    "brb" => "Be Right Back",
    "iee" => "I'm easily extendable"
);

Then when you need the text for a particular key you can just type

$descriptive_text = $descriptions[$var1];

Updated:

To set it to the original if there is no value in $descriptions, do the following:

$descriptive_text = (is_null($descriptions[$var1])) ? $var1 : $descriptions[$var1];

edited Apr 6, 2012 at 14:32

answered Apr 6, 2012 at 13:56

Chuck Callebs

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1 Comment

user1040157 Over a year ago

and if the variable not contains "n/a" how can i go with the actual value?

TJHeuvel · Accepted Answer · 2012-04-06 13:54:25Z

0

You should use arrays for this.

$array = array("abc", "n/a", "das", "n/a");
foreach($array as $key => $value)
{
 if($value == "n/a")
 {
  echo "Do Something!";
 }
}

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