constructor inheriting self python

Question

I made a class which looks something like.

class NewInt:
  def __init__(self, x,y):
    self.holders = {"x":x,"y":y}

Now, I have a number say a dictionary. So everything is exactly same

except its not NewInt but a dict.Somethng like

 A  {"x": 3,"y":4}

So it is exactly of type NewInt except its a dictionary.

Is there a way i can do something like

this_int = NewInt(A)

I forgot but there was a special name to such constructor where assignment is done ?? Thanks

I don't quite understand you... Try this_int = NewInt(**A). — Oleh Prypin
– Oleh Prypin, Commented Apr 6, 2012 at 22:07
For more general cases, you might want to watch PEP 3124 which would introduce overloading to python, making it easier to make constructors that vary based on input. — Gareth Latty
– Gareth Latty, Commented Apr 6, 2012 at 22:13

phihag · Accepted Answer · 2012-04-06 22:09:03Z

4

You can use keyword arguments:

A = {"x": 3,"y":4}
this_int = NewInt(**A)

By the way, it's looking like you're reimplementing complex numbers. Those are already built in to Python, try complex(3,4) or 3+4j.

answered Apr 6, 2012 at 22:09

phihag

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1 Comment

Casey Kuball Over a year ago

You may need to add an additional **kwargs argument for this to work when the dictionary has extra keywords, otherwise you'll get a TypeError for the unexpected extra keyword argument(s).

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