Passing a variable to PHP with jQuery .load

Question

I have a page ("main.php") which loads content from an external PHP file ("rpc.php"). Using the below syntax on main.php successfully pulls in content from rpc.php:

$("#portfolioContent").load("rpc.php?o="+day+"");

On rpc.php I have an if statement (part of a long switch function), as follows:

if ( $pagename == "home" ) {
break;
}

This break is not occuring because the variable has not been set. rpc.php is used by various parent pages so the variables need to be set on those. On a parent page I have tried using the following code to attempt to set the variable and pass it to rpc.php but to no avail:

$("#portfolioContent").load("rpc.php?o="+day+"$pagename="home"");

Can anybody point me in the right direction? Thank you.

Okan Kocyigit · Accepted Answer · 2012-04-07 14:51:33Z

2

It should be like this,

$("#portfolioContent").load("rpc.php?o="+day+"&pagename=home");

answered Apr 7, 2012 at 14:51

Okan Kocyigit

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Comments

Alfred · Accepted Answer · 2012-08-16 11:49:15Z

1

Your syntax is wrong. Try this:

$("#portfolioContent").load("rpc.php?o="+day+"&pagename=home");

Notice i substituted the $ with a &

Cheers

edited Aug 16, 2012 at 11:49

Alfred

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answered Apr 7, 2012 at 14:54

John Shepard

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Comments

Alfred · Accepted Answer · 2012-08-16 11:49:58Z

1

change this line

$("#portfolioContent").load("rpc.php?o="+day+"$pagename="home"");

to this

$("#portfolioContent").load("rpc.php?o="+day+"pagename="home");

then access the variable with $_GET['pagename']

edited Aug 16, 2012 at 11:49

Alfred

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answered Apr 7, 2012 at 14:53

Krishna Deepak

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1 Comment

Chris Over a year ago

The first part of your code didn't seem to work but the $_GET['pagename'] part was very helpful, thank you :)

ServAce85 · Accepted Answer · 2012-05-22 09:51:48Z

0

To access variables from the URL in PHP just do: $_GET['variablename']

For example, with the URL http://www.example.com?hello=hellWorld

echo $_GET['hello'];

would print helloWorld

Also, you use & to separate variables, not $

edited May 22, 2012 at 9:51

ServAce85

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answered Apr 7, 2012 at 14:53

user1110192

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