Php not printing correct value when changing value from javascript

Question

I have an html page that submits a form through javascript. Before submitting the form I change the value of a hidden tag which I then try to get in php but it doesn't work. It appears blank.

Here is the javascript

function remove(){



remove.value = 'true';


  document.newrow.submit() ;


}

The value for remove is set successfully however when I submit the form I get a blank value.

Here is the php code to retrieve the value.

$test = $_POST['remove'];


echo $test;

any idea why the value is blank?

Thanks

<form name = 'newrow' action = 'update.php' method = 'post'>


<input type='hidden' name='remove' id = 'remove' /><a href='javascript:remove()'><img src = 'images/delete.png' / ></a>

Can we have more source? For all we know, it's a GET form and remove is a DOM element that isn't even in it. — Waleed Khan
– Waleed Khan, Commented Apr 9, 2012 at 4:28

Shubham · Accepted Answer · 2012-04-09 04:30:27Z

2

remove.value = 'true';

Is too ambigous. Try using document.getElementById('remove').value, assuming that the element has remove as its ID.

answered Apr 9, 2012 at 4:30

Shubham

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2 Comments

Shubham Over a year ago

@user541597: are you sure that form gets submitted?

user541597 Over a year ago

yes I get to the php page, and I get other values for other tags.

Naveen Kumar · Accepted Answer · 2012-04-09 05:13:12Z

0

You should do like this

<input type='hidden' name='random' id='random' />
<input type='submit' name='enter' value="Enter" onclick="remove" />

function remove() { document.getElementById("random").value='true'; }

//PHP part

if(isset($_POST['enter']))
{
   $ramdom=$_POST['random'];
}

The error probably is that you are submitting it twice

--Update for anchor tag

Here is what you're missing:

A link does not submit the form with input data, it just changes the url.
Submit the form.
Override the default <a> behavior (for example, using return false).

function random()  
{  
    document.getElementById("random").value = 'true';  
    document.getElementById("thisForm").submit();
    return false;
}

You can call it using:

<a href="" name="enter" onclick="return random();">Enter </a>

edited Apr 9, 2012 at 5:13

answered Apr 9, 2012 at 4:30

Naveen Kumar

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3 Comments

user541597 Over a year ago

how am I submitting it twice? I'm actually submitting once through javascript only.

user541597 Over a year ago

I'm using an anchor tag to submit with javascript not a submit button.

Naveen Kumar Over a year ago

Anchor tab does not post data use a submit button and make it look like a anchor tab using stylesheet

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