xpath expression fails with checking attribute value

Question

I need to get every operator_id tags attribute @name in group tag with @title attribute equals some string, an example below fails to do this:

List list = doc.selectNodes("//root//menu//group[@title=" + menuTitle + "]//operator_id//@name");

XML Structure:

  <group id="980" title="Переводы" image="" sh_n="1" enable="1" visible="0" image_bg="" type="">
  <operator_id id="10000047" name="Перевод физ лицу" image="individual.png" sh_n="1" enable="1" visible="1" /> 
  <operator_id id="10000048" name="Перевод юр лицу" image="organizations.png" sh_n="1" enable="1" visible="1" /> 
  <operator_id id="10000078" name="Перевод внутри банка" image="innerbank.png" sh_n="1" enable="1" visible="1" /> 
  <operator_id id="10000049" name="Налоговый платеж" image="taxes1.png" sh_n="1" enable="1" visible="1" /> 
  </group>

What am I doing wrong?

Jon Skeet · Accepted Answer · 2012-04-12 11:42:33Z

2

I'm not an XPath expert by any means, but I don't think you want to use double-slashes all the way through your query. Have you tried:

List list = doc.selectNodes(
   "//root/menu/group[@title=" + menuTitle + "]/operator_id/@name");

? Even the // at the start can be just / if it's really meant to be the root element.

Additionally, I suspect you should add quoting for the value, e.g.

List list = doc.selectNodes(
   "//root/menu/group[@title='" + menuTitle + "']/operator_id/@name");

or

List list = doc.selectNodes(
   "//root/menu/group[@title=\"" + menuTitle + "\"]/operator_id/@name");

Those would be more like the samples in the XPath specification.

answered Apr 12, 2012 at 11:42

Jon Skeet

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1 Comment

Arthur Kushman Over a year ago

Yeah I've already tried it out and it works - thank U for response.

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