Looping through array updating values PHP

Question

say I have an array in php like this

$info['name'] = 'test %value%';
$info['city'] = 'city test %value%';
$info['other'] = '%value% city test';

all I want to do is loop through this array and replace all the instances of %value% with a supplied string, saving it into the same array.

What would be the best way to do that? :)

Thanks

mellamokb · Accepted Answer · 2012-04-18 02:54:16Z

15

foreach ($info as $key => $value)
  $info[$key] = str_replace('%value%', 'MyValue', $value);

Demo: http://ideone.com/65F3L

answered Apr 18, 2012 at 2:54

mellamokb

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1 Comment

James Wilson Over a year ago

If you want to only replace instances where the entire $value equals your search criteria, rather than instance within the strong, then just wrap the second line in: if ($value == "%value%") {

Paul · Accepted Answer · 2012-04-18 03:03:47Z

4

This seems to be the cleanest way to me, but it requires PHP 5.3 or higher:

$info = array_map(function($x) use ($newValue){ 
    return str_replace('%value%', $newValue, $x);
}, $info);

Codepad

answered Apr 18, 2012 at 3:03

Paul

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