AJAX / Jquery XML parse

Question

I try parsing the following type of XML (data from getMembers.php):

<?xml version="1.0" encoding="ISO-8859-1"?>
<members>
   <id>3422345</id>
   <name>Bill Gates</name>
   <id>232311</id>
   <name>Bob Barker</name>
</members>

And I use the code below to parse it:

<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script>
    <script type="text/javascript">
    $(document).ready(function () {
        $.ajax({
            type: "GET",
            url: "getMembers.php",
            cache: false,
            dataType: "xml",
            success: function(xml) {
                $(xml).find('members').each(function(){
                    var name = $(this).find("name").text()
                    alert(name);
                });
            }
        });
    });
</script>

No error but I get both names at the same time.

Like:

Bill GatesBob Barker <--first loop>

Instead of

Bill Gates <--first loop>

Bob Barker <--second loop>

Any help would be great!

Is that a typo : <memebers> ?

fmgp
– fmgp

2012-04-19 07:59:39 +00:00
Commented Apr 19, 2012 at 7:59 — fmgp
– fmgp, Commented Apr 19, 2012 at 7:59
Oops sorry about that. It's been corrected.

StealthRT
– StealthRT

2012-04-19 08:09:05 +00:00
Commented Apr 19, 2012 at 8:09 — StealthRT
– StealthRT, Commented Apr 19, 2012 at 8:09

fmgp · Accepted Answer · 2012-04-19 08:15:49Z

35

I think you iterate over members, not names:

success: function(xml) {
                $(xml).find('members').each(function(){
                    $(this).find("name").each(function(){
                        var name = $(this).text();
                        alert(name);
                    });
                });
            }

Or maybe your XML should looks like:

<members>
   <id>3422345</id>
   <name>Bill Gates</name>
</members>
<members>
   <id>232311</id>
   <name>Bob Barker</name>
</members>

answered Apr 19, 2012 at 8:15

fmgp

1,63617 silver badges17 bronze badges

Sign up to request clarification or add additional context in comments.

2 Comments

StealthRT Over a year ago

That was it. Thanks fmgp! :o)

Thomas Moser Over a year ago

i also recommend to use the following valid xml format as seen in the answer from user2780947: <members> <member> <id>123</id> <name>First Last</name> </member> <member> <id>124</id> <name>Bill Gates</name> </member> </members>

Victor Cardenas · Accepted Answer · 2016-10-06 13:56:08Z

2

This way show names:

<script type="text/javascript">
$(document).ready(function () {
    $.ajax({
        type: "GET",
        url: "getMembers.php",
        cache: false,
        dataType: "xml",
        success: function(xml) {
            $(xml).find('name').each(function(){
                        var name = $(this).text();
                        alert(name);
            });
        }
    });
});

answered Oct 6, 2016 at 13:56

Victor Cardenas

211 bronze badge

Comments

mr.stanislav · Accepted Answer · 2018-03-03 23:23:24Z

2

Just wondering if you successfully parsed that XML data.

The valid XML format is below:

<?xml version="1.0" encoding="ISO-8859-1"?>
<members>
  <member>
   <id>3422345</id>
   <name>Bill Gates</name>
  </member>
  <member>
   <id>232311</id>
   <name>Bob Barker</name>
 </member>
</members>

answered Mar 3, 2018 at 23:23

mr.stanislav

398 bronze badges

Collectives™ on Stack Overflow

AJAX / Jquery XML parse

3 Answers 3

2 Comments

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

3 Answers 3

2 Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related