How to call $_SESSION in javascript

Question

I have two separate pages, one page is where it uploads the file and the other page displays the information.

In the imageupload.php page, I have this session below:

$_SESSION['fileImage']['name'] = $_FILES['fileImage']['name'];

I also have a javascript function which calls back to the javascript functiom:

<script language="javascript" type="text/javascript">window.top.stopImageUpload();</script>

Now on a seperate page (QandATable.php), I have a javascript function, but my question is how can I call the $_SESSION code above in the javascript function so I can append it to $('.list')?

Below is javascript function:

 function stopImageUpload(success){

var result = '';
if (success == 1){
result = '<span class="msg">The file was uploaded successfully!</span><br/><br/>';
$('.listImage').append('<br/>');
          }
else {
result = '<span class="emsg">There was an error during file upload!</span><br/><br/>';
          }

return true;

    }

FYI: window.top.stopImageUpload; doesn't do anything. I assume you meant window.top.stopImageUpload();? — gen_Eric
– gen_Eric, Commented Apr 20, 2012 at 21:54

Adam Magaluk · Accepted Answer · 2012-04-21 15:57:10Z

2

You cant, because $_SESSION is a server side variable but you can access it by.

For the entire session variable

<script type="text/javascript" >
  var session = <?php echo json_encode($_SESSION); ?>;
</script>

For a particular variable in session.

<script type="text/javascript" >
  var session_var = <?php echo json_encode($_SESSION['VAR_NAME']); ?>;
</script>

Now you have js variable called session with that information. However it is not advisable in most situation to output all that info to public pages.

edited Apr 21, 2012 at 15:57

answered Apr 20, 2012 at 21:57

Adam Magaluk

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4 Comments

user1341521 Over a year ago

So for $_SESSION['fileImage']['name'] = $_FILES['fileImage']['name'];, will it be coded as var session = <?php echo json_encode($_SESSION['fileImage']['name'] ?>;

user1341521 Over a year ago

I am getting an invalid regular expression flag w error when I include code above

Adam Magaluk Over a year ago

What is $_SESSION['fileImage']['name'] returning in php

user1341521 Over a year ago

It returns the name of the file uploaded

Mārtiņš Briedis · Accepted Answer · 2015-05-05 10:16:52Z

2

Session variables are stored on the server. JavaScript is executed on the cliend side, so it knows nothing about the server side. It know only as much as you pass to it.

To pass a variable to javascript, use an ajax request, or simply output the values:

<script>
var sesionValue = <?=json_encode($_SESSION['value']);?>;
</script>

edited May 5, 2015 at 10:16

answered Apr 20, 2012 at 21:57

Mārtiņš Briedis

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1 Comment

Myobis Over a year ago

Here, you are seriously missing "output escaping" : what it the value contains an apostrophe ?! depending on how this value is populated, this can be the source of real security issues (js code injection, ...) some escaping function like addslashes() needs to be used.. or more generally (depending on the value type), json_encode()

Alex · Accepted Answer · 2012-04-30 19:16:54Z

You should look into using JQuery, as it makes these AJAX-like tasks much easier.

See my function I wrote just today to do something similar to what you're asking.

This takes some PHP output (returned in the success part of the call to ajax(). The format it takes is in JSON, which is compatible by both PHP and JavaScript (JSON: JavaScript Object Notation).

function viewClientDetails(id) {
    var clientParams;
    clientParams.clientID = id;
    $.ajax({
        url: BASE_URL + '/clients/get-client-details.php',
        type: 'POST',
        data: clientParams,
        dataType: 'JSON',
        success: function(myClient) {
            var name = myClient.name;

            $('td#name').html(name);

        },
        error: function(e) {
            console.log(e.responseText);
        }
    })
}

In my PHP file (called /clients/get-client-details.php) I have something like this:

<?php
...
$myClient = array('name' => 'Mr Foobar');
print json_encode($myClient);

?>

This simply writes my PHP object to JSON format.

In the JS code above, the code inserts a part of the JSON data into an HTML table-data element whose CSS selector ID is #name, with the line: $('td#name').html(name);

Apologies if this confuses you more, I thought I'd show an example of what you can try some time..

This may help you a bit along the way...keep trying things, you'll get there :)

Anthony Grist · Accepted Answer · 2012-04-20 21:57:51Z

0

You can't. $_SESSION is a PHP variable, and that code runs server-side.

You'll need to store the value as a Javascript variable in the output from your PHP file, then access that variable in your Javascript.

answered Apr 20, 2012 at 21:57

Anthony Grist

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3 Comments

gen_Eric Over a year ago

$_SESSION is just a variable.

Mārtiņš Briedis Over a year ago

$_SESSION is neither a method, nor it's a function. It's a variable (superglobal).

Anthony Grist Over a year ago

You're both correct, I was mixing up my brackets and getting confused - I'm going to blame the fact that it's late.

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